http://www.springerlink.com/content/q185862551668217/
It is by far the most natural proof I have come across of this theorem even though the fundamental idea is from the theory of regularized determinants.
A few preliminaries
The notation introduced here will be used throughout.
Observe that for a given Hurwitz zeta function, Z_λ (s, t) = sum_[λ_n] (λ_n + t)^(-s),
∂[Z_λ (0, t)]/∂s = - sum_[λ_n] log (λ_n + t)
So we define the zeta-regularized product for the sequence (λ_n)_{n=0,...},
prodz_[λ_n] (λ_n + t) := exp (- ∂[Z_λ (0, t)]/∂s)
For convenience when λ_n = n we shall denote the resulting classical Hurwitz zeta function by Z.
The main result that will be employed is Lerch's formula,
∂[Z(0, t)]/∂s = -(1/2).log (2π) + log Γ(t)
where log is the natural logarithm and Γ is the Gamma function as defined at http://en.wikipedia.org/wiki/Gamma_function
Observe that for a given Hurwitz zeta function, Z_λ (s, t) = sum_[λ_n] (λ_n + t)^(-s),
∂[Z_λ (0, t)]/∂s = - sum_[λ_n] log (λ_n + t)
So we define the zeta-regularized product for the sequence (λ_n)_{n=0,...},
prodz_[λ_n] (λ_n + t) := exp (- ∂[Z_λ (0, t)]/∂s)
For convenience when λ_n = n we shall denote the resulting classical Hurwitz zeta function by Z.
The main result that will be employed is Lerch's formula,
∂[Z(0, t)]/∂s = -(1/2).log (2π) + log Γ(t)
where log is the natural logarithm and Γ is the Gamma function as defined at http://en.wikipedia.org/wiki/Gamma_function
Note that Z'(0) = -(1/2).log (2π) where Z is the Riemann zeta function.
For a proof the reader can refer to http://ocw.nctu.edu.tw/upload/fourier/supplement/Zeta-Function.pdf or the chapter on the Zeta and Gamma functions in S Lang's Complex Analysis (4th ed.), Springer Graduate Texts in Mathematics.
(await latter half for proof)...
For a proof the reader can refer to http://ocw.nctu.edu.tw/upload/fourier/supplement/Zeta-Function.pdf or the chapter on the Zeta and Gamma functions in S Lang's Complex Analysis (4th ed.), Springer Graduate Texts in Mathematics.
We now have the immediate corollary that,
prodz_[n=0 to +infinity] (n + t) = √(2π) / Γ(t) ------- (1)
(await latter half for proof)...
No comments:
Post a Comment